Factorising nbsp- x-2 - 16x - 63 we get- -x - 7- and nbsp-x - 7-x - 9-x - 7-x - 9-x - 9-x - 9-

The correct option is C (x + 9)Given: x^2 + 16x + 63. nbsp; Comparing the given expression with the identity x^2+(a+b)x+ab we get, nbsp;ab=63 and (a+b)=16. ...

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Standard VII

Mathematics

Factorisation of Algebraic Expressions Using Identities

Factorising ...

Question

Factorising $x^{2} + 16 x + 63$ we get, $(x + 7)$ and .

(x - 7) (x + 9)

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(x + 7) (x - 9)

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(x + 9)

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(x - 9)

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Solution

The correct option is C $(x + 9)$
Given: $x^{2} + 16 x + 63.$

Comparing the given expression with the identity $x^{2} + (a + b) x + a b$ we get, $a b = 63 a n d (a + b) = 16.$
$S o, (9 + 7) = 16 a n d (9) (7) = 63$

Hence,
$x^{2} + 16 x + 63$
$= x^{2} + 9 x + 7 x + 63$
$= x (x + 9) + 7 (x + 9)$
$= (x + 7) (x + 9)$

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Q. Factorising

x^{2} + 16 x + 63

we get,

(x + 7)

and .

Express the following difference in simplest form $?$

$\frac{7 x}{x^{2} - 9 x + 14} - \frac{4}{x - 7}$

Simplify $\frac{7 x}{x^{2} - 9 x + 14} - \frac{4}{x - 7}$ .

Q. Find the quotient when the polynomial

4 x^{3} + x^{2} - 3

is divided by

x - 2

using synthetic division method.

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Factorising x2+16x+63 we get, (x+7) and .

The correct option is C (x+9)Given: x2+16x+63. Comparing the given expression with the identity x2+(a+b)x+ab we get, ab=63 and (a+b)=16. So, (9+7)=16 and (9)(7)=63 Hence, x2+16x+63 =x2+9x+7x+63 =x(x+9)+7(x+9) =(x+7)(x+9)

Factorising $x^{2} + 16 x + 63$ we get, $(x + 7)$ and .