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Algebraic Identities

Factorize 8a3...

Question

Factorize $8 a^{3} - b^{3} - 4 a x + 2 b x$

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Solution

$8 a^{3} - b^{3} - 4 a x + 2 b x (2 a)^{3} - (b)^{3} - 2 x (2 a - b) = (2 a - b) [(2 a)^{2} + 2 a \times b + (b)^{2}] - 2 x (2 a - b) = (2 a - b) [4 a^{2} + 2 a b + b^{2}] - 2 x (2 a - b) = (2 a - b) [4 a^{2} + 2 a b + b^{2} - 2 x]$

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Similar questions

Q. Factorize:
8a³ − b³ − 4ax + 2bx

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8 a^{3} + b^{3} - 6 a b + 1

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