Factorize the following:
2x³y² − 4x²y³ + 8xy⁴

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Solution

The greatest common factor of the terms 2x³y², -4x²y³ and 8xy⁴of the expression 2x³y² - 4x²y³+ 8xy⁴y⁶⁴ is 2xy².

Now,
2x³y² = 2xy² $\times$ x²
-4x²y³= 2xy² $\times$ -2xy
8xy⁴ = 2xy² $\times$ 4y²

Hence, the expression 2x³y² - 4x²y³ + 8xy⁴ can be factorised as 2xy²(x² - 2xy + 4y²).

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Similar questions

Factorize the following:

$2 x^{3} y^{2} - 4 x^{2} y^{3} + 8 x y^{4}$

\sqrt{3} x^{2} y^{2} - \sqrt{2} x^{3} y^{2} + \sqrt{5} x^{3} y^{3} b y - \sqrt{2} x^{2} y^{2}

- \sqrt{6} x^{4} y^{4} + 2 x^{5} y^{4} - \sqrt{10} x^{5} y^{5}

x^{2} y^{3}

x y^{3}

x^{2} y

x^{2} y^{3}

x y^{3}

x^{2} y

u = 3 y

v = 3 x

u = 3 x t

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