Factorize- x2 - 6 -2x - 10

X^2 + 6 √(2)x + 10 = x^2 +5 √(2)x + √(2) x + 10 ∵ 6 √(2) = 5 √(2)+ √(2) 10 = 5 √(2)×√(2) = x(x + 5 √(2)) + √(2)(x + 5 √(2)) = (x + 5 √(2)) (x + √(2)) ...

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Byju's Answer

Standard IX

Mathematics

Factorisation of Quadratic Polynomials- Middle Term Splitting

Factorize: x2...

Question

Factorize:

$x^{2} + 6 \sqrt{2} x + 10$

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Solution

$x^{2} + 6 \sqrt{2} x + 10 = x^{2} + 5 \sqrt{2} x + \sqrt{2} x + 10 {\begin{matrix} ∵ 6 \sqrt{2} = 5 \sqrt{2} + \sqrt{2} 10 = 5 \sqrt{2} \times \sqrt{2} \end{matrix}} = x (x + 5 \sqrt{2}) + \sqrt{2} (x + 5 \sqrt{2}) = (x + 5 \sqrt{2}) (x + \sqrt{2})$

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Factorize: x2+6√2x+10

x2+6√2x+10=x2+5√2x+√2x+10{∵6√2=5√2+√210=5√2×√2}=x(x+5√2)+√2(x+5√2)=(x+5√2)(x+√2)

Factorize:

$x^{2} + 6 \sqrt{2} x + 10$

$x^{2} + 6 \sqrt{2} x + 10 = x^{2} + 5 \sqrt{2} x + \sqrt{2} x + 10 {\begin{matrix} ∵ 6 \sqrt{2} = 5 \sqrt{2} + \sqrt{2} 10 = 5 \sqrt{2} \times \sqrt{2} \end{matrix}} = x (x + 5 \sqrt{2}) + \sqrt{2} (x + 5 \sqrt{2}) = (x + 5 \sqrt{2}) (x + \sqrt{2})$