Factorize y3-3 y2-2 y-6-x y-3 xA- -3- y x -2- y 2B- y -3 y 2-2- x C- -3-yy2-2-xD- 3-yx-2-y2

The correct options are B (y 3)(y^2 + 2 x) C (3 y)(y^2 + 2 x) D (3 y)(x 2 y^2) ⇒ y^3 3y^2 + 2y 6 xy + 3x ⇒ (y^3 3y^2) + (2y 6) (xy ...

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Factorisation by Grouping

Factorize y3-...

Question

Factorize:

$y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x$

$- (3 - y) (x - 2 - y^{2})$

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$(y - 3) (y^{2} + 2 - x)$

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$- (3 - y) (y^{2} + 2 - x)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(3 - y) (x - 2 - y^{2})$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

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Solution

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Similar questions

y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x

(i) x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2}) (i i) x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

y^{3} - 3 y^{2} + 2 y - 6 - x y + 3 x

y = y (x)

x \sqrt{x^{2} - 1} d y - y \sqrt{y^{2} - 1} d x = 0

y (2) = \frac{2}{\sqrt{3}}

y (x) = sec (s e c^{- 1} x - \frac{π}{6})

y (x)

\frac{1}{y} = \frac{2 \sqrt{3}}{x} - \sqrt{1 - \frac{1}{x^{2}}}

Verify x^3 × y^3 =(x+y)(x^2-xy + y^3)

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