Question

Factorize $z^2+3\sqrt{3}z-12$

Answer 1

Given expression is,

$z^2+3\sqrt{3}z-12$

$=z^2+4\sqrt{3}z-\sqrt{3}z-12$

$=(z+4\sqrt{3})$$(z-\sqrt{3})$

So the zeroes are,

$z+4\sqrt{3}=0\Rightarrow z=-4\sqrt{3}$

$z-\sqrt{3}=0\Rightarrow z=\sqrt{3}$