Question

Fill in the blanks

$12+\left(-12\right)=\_\_\_$

Answer 1

$12+\left(-12\right)=\_\_\_$

Let x is required value

$12+\left(-12\right)\mathbf{}=\mathbf{x}$

On solving we have

$12-12=\mathbf{x}$

$\mathbf{x}=0$

Hence $0$ is the required value