Fill in the blanks.
$5^{2} + 6^{2} + ()^{2} = (31)^{2}$

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Solution

The correct option is A 30
Base of third number is the product of bases of first and second number.
$∴$ Base of third number is
$5 \times 6 = 30$

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Similar questions

6^{2} + 7^{2} + 42^{2} = ()^{2}

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} + 20^{2} = 21^{2}

5^{2} + 6^{2} + 30^{2} = 31^{2}

6^{2} + 7^{2} + 42^{2} = . . .^{2}

Fill in the blanks:-

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

Fill in the blanks: $6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} +

= 21^{2}

5^{2} +

+ 30^{2} = 31^{2}

6^{2} + 7^{2} +

=

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