Fill in the blanks: $6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

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Solution

6 and 7 are consecutive numbers

$6 \times 7 = 42; 6^{2} + 7^{2} + 42^{2} = 43^{2}$

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Similar questions

Fill in the blanks:-

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

6^{2} + 7^{2} +

= 43^{2}

6^{2} + 7^{2} + 42^{2} = ()^{2}

Choose the right option for the blank.

$6^{2}$ + $7^{2}$ + $($ __ $)^{2}$ = $43^{2}$

$6^{2}$ + $7^{2}$ + $($ ___ $)^{2}$ = $43^{2}$

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