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Finding the Value of an Expression

Fill in the b...

Question

Fill in the blanks:

$(i) 6 \times 3 = - ------ - and 6 x \times 3 x = - ------ -$

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Solution

Find the product of $6$ and $3$
$6 \times 3 = 18$

Find the product of $6 x$ and $3 x$
i.e., $6 x \times 3 x$

The multiplication of monomials can be performed
by multiplication of their coefficients and literals

$∴ 6 x \times 3 x$
$= (6 \times 3) \times (x \times x)$
$= 18 \times x^{2}$
$= 18 x^{2}$

Hence $6 \times 3 = 18$ and $6 x \times 3 x = 18 x^{2}$

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Q. Fill in the blanks:

(i) (−6) × (......) = 6
(ii) (−18) × (......) = (−18)
(iii) (−8) × (−9) = (−9) × (......)
(iv) 7 × (−3) = (−3) × (......)
(v) {(−5)×3} × (−6) = (......) × {3×(−6)}
(vi) (−5) × (......) = 0

Q. Fill in the blanks:

(i) (......) ÷

(\frac{- 7}{5}) = \frac{10}{19}

(ii) (......) ÷

(- 3) = \frac{- 4}{15}

\frac{9}{8} \div (. . . . . .) = \frac{- 3}{2}

(- 12) \div (. . . . . .) = \frac{- 6}{5}

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(i)

\frac{9}{8} + (. . .) = \frac{- 3}{2}

(. . .) \div (\frac{- 7}{5}) = \frac{10}{19}

(. . .) \div (- 3) = \frac{- 4}{15}

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(i)

\frac{- 5}{7} = \frac{\dots}{35} = \frac{\dots}{49}

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\frac{6}{- 13} = \frac{- 12}{\dots} = \frac{24}{\dots}

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Fill in the blanks:
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Finding the Value of an Expression

Standard VII Mathematics

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