Question

Find $\angle DCE$ when $AB\parallel DE$

Answer 1

From given conditions,

$\angle BAE=\angle DEC={35}^o$ ..........[by alternate angle]

Using sum of angles in triangle,

$⟹\angle CDE+\angle CED+\angle DEC={180}^o$

$⟹{53}^0+{35}^0+\angle CED={180}^o$

Hence,

$\angle CED={92}^o$