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Question

Find dydx if xsiny+ysinx=0

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Solution

Given xsiny+ysinx=0

Now differentiate the equation with respective to x

We get siny+xcosydydx+dydxsinx+ycosx=0

dydx(xcosy+sinx)+(siny+ycosx)=0

dydx=(siny+ycosxxcosy+sinx)


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