Find 12of22.
12of22=12×22=1×222=222=11∴12of22=11
Simplify : 34÷( 16÷12 )
Simplify :( 34÷12-13) × 67
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ