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Question

Find the HCF of (x−2)2, x2−4 and x2+x−6.


A

y+2

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B

y+3

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C

y

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D

y2+2y

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Solution

The correct option is C

y


Let, x = y+2

First expression: (x2)2=((y+2)2)2=y2

Second expression: x24=((y+2)24)=y2+4y

Third expression: x2+x6=(y+2)2+x6=y2+5y

from the above expressions y is the highest common factor.


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