Find the HCF of (x−2)2, x2−4 and x2+x−6.
y
Let, x = y+2
First expression: (x−2)2=((y+2)−2)2=y2
Second expression: x2−4=((y+2)2−4)=y2+4y
Third expression: x2+x−6=(y+2)2+x−6=y2+5y
∴ from the above expressions y is the highest common factor.