Question

Find H.C.F of $(x-2{)}^2$, $x^2-4$ and $x^2+x-6$. Put $x=y+2$.

• A. $y+2$
• B. $y+3$
• C. $y$
• D. $y^2+2y$

Answer 1

The correct option is C

$y$

$(x^2-4)=(x-2)(x+2)$

$x^2+x-6=(x-2)(x+3)$

H.C.F for $(x-2{)}^2$, $x^2-4$ and $x^2+x-6$ is $x-2$.

Now $x=y+2$. So H.C.F is y