Find if (x+2) (x+3) is a factor of x/\3+ax/\2+bx-12 find the value of a and b
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Solution
if (x+2) (x+3) is a factor of x/\3+ax/\2+bx-12 , then -2 and -3 are roots of equation. Put -2 in the equation you'll get -8+4a-2b-12=0 2a-b=10 ---- (i)
Put -3 in the equation -27+9a-3b-12=0 3a-b=13 ----(ii)