Question

Find n :-
$4n^2-8n+3$=0

Answer 1

Consider the given expression.

$\Rightarrow 4n^2-8n+3$

$\Rightarrow 4n^2-6n-2n+3$

$\Rightarrow 2n(n-3)-1(n-3)$

$\Rightarrow (n-3)(2n-1)$

When,

$n-3=0$

$n=3$

When,

$2n-1=0$

$n=\frac{1}{2}$

Hence, this is the answer.