Find the $11^{t h}$ term of -5, -1, 3, 7.......................

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 35
Given series is an A.P. Where First term (a) = - 5 and Common difference (d) = 4

nth term of A.P. $(T_{n}) = a + (n - 1) d$

$T_{11} = - 5 + (11 - 1) \times 4 = - 5 + 40 = 35.$

Suggest Corrections

Similar questions

- 5, - 1, 3, 7, \dots

a

d

- 5, - 1, 3, 7, . . . . .

If the $5^{t h}$ and $11^{t h}$ term in an A.P are 11 and 5. Find the $16^{t h}$ term.

a

d

- 5, - 1, 3, 7......

Join BYJU'S Learning Program