Find the 11th term of -5, -1, 3, 7.......................
Given series is an A.P. Where First term (a) = - 5 and Common difference (d) = 4
nth term of A.P. (Tn)=a+(n−1)d
T11=−5+(11−1)×4=−5+40=35.
If the 5th and 11th term in an A.P are 11 and 5. Find the 16th term.