Question

Find the $\angle DCE$ ?

Answer 1

Given, $AB\parallel DE\angle CDE={53}^o,\angle BAE={35}^o$

Since, $AB\parallel DE$ and $AE$ is transversal,

So, $\angle BAE=\angle AED={35}^o\left[alternateinteriorangles\right]$

$\therefore \angle DCE={180}^o-(\angle CED+\angle CDE)={180}^o-({35}^o+{53}^o)={92}^o.$