Question

Find the area of a quadrilateral $ABCD$

Answer 1

Area of trapezium $ABCD=\frac{h}{2}\times$ (sum of parallel sides)

$=\frac{3}{2}\times (4+5)$

$=\frac{3}{2}\times 9$

$=\frac{27}{2}c{m}^2$

$=13.5c{m}^2$