Find the equation of director circle of the circle (x−1)2+(y−2)2=4
(x−1)2+(y−2)2=8
Given the circle (x−1)2+(y−2)2=4
Center of original circle =(1,2) and radius =√2
We know,
Director circle of a circle is the locus of the point of intersection of two perpendicular tangents.
It is the concentric circle having radius equal to √2 times the orginal circle.
Center of director circle =(1,2) and radius =2√2
Equation of the director circle is (x−1)2+(y−2)2=(2√2)2
(x−1)2+(y−2)2=8
Option B is correct