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General Form of a Straight Line

Find the equa...

Question

Find the equation of locus of 'P' $A = (4, 0), B (- 4, 0)$ and $P A - P B = 0$ .

x = 0

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y = 0

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x = 2

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x = 4

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Solution

The correct option is A $x = 0$
$l e t p o i n t A b e (h, k), t h e n P A - P B = 0 P A^{2} = P B^{2} (h - 4)^{2} + (k - 0)^{2} = (h + 4)^{2} + (k - 0)^{2} = h^{2} - 8 h + 16 = h^{2} + 8 h + 16 ∴ 16 h = 0 h = 0 r e p l a c e h b y x, w e g e t x = 0$

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Similar questions

P

A = (4, 0), B = (- 4, 0)

| P A - P B | = 4

P

A = (4, 0), B (- 4, 0)

| P A + P B | = 4

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\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1

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P A + P B = 10 .

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