Find the LCM of23,49,56,712
Solve for LCM of given numbers
The given fractions are,
23,49,56,712
LCM23,49,56,712=L.C.M(2,4,5,7)H.C.F(3,9,6,12)
LCM2,4,5,7=2×2×5×7=140
HCF(3,9,6,12)=3
Therefore, LCM23,49,56,712=1403
Hence, the LCM of23,49,56,712 is1403.
The sum of the series 23!+45!+67!+... to ∞ = ae. Find (a+3)2.