CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the LCM of polynomials P(y)=(y327)(y23y+2) and Q(y)=(y2+3y+9)(y25y+6).

Open in App
Solution

We have
P(y)=(y327)(y23y+2)=(y3)(y2+3y+9)(y2)(y1),
Q(y)=(y2+3y+9)(y25y+6)=(y2+3y+9)(y3)(y2).
We observe that y3,y2,y1 and y2+3y+9 are the irreducible factors each having maximum exponent equal to 1. Hence their product
(y3)(y2)(y2+3y+9)
is the LCM of given polynomials.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lowest Common Multiple
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon