Find the mobility of the conduction electrons in a copper conductor if in Hall effect measurements performed in the magnetic field of induction $B = 100 m T$ the transverse electric field strength of the given conductor turned out to be $η = {3.1.10}^{3}$ times less than that of the longitudinal electric field.

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Solution

By definition, $m o b i l i t y = \frac{d r i f t v e l o c i t y}{E l e c t r i c f i e l d c o m p o n e n t c a u s i n g t h i s d r i f t}$ or $μ = \frac{v}{E_{L}}$
On other hand, $E_{T} = v B = \frac{E_{L}}{η}$ , as given so, $μ = \frac{1}{η B} = 3.2 \times 10^{- 3} m^{2} / (V \cdot s)$

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