Question

Find the perimeter of a rectangle whose area $=2600m^2$ and breadth $=50m$.

Answer 1

Step 1: Calculating the length of the rectangle
The area of the rectangle is given by:
$A=Length\times Breadth$
$\Rightarrow 2600=l\times 50$
$\Rightarrow l=\frac{2600}{50}$
$\Rightarrow l=\frac{260}{5}=52m$

Step 2: Calculating the perimeter of the rectangle:
The perimeter of the rectangle is given by:
$P=2(Length+Breadth)$
$\Rightarrow P=2(52+50)$
$\Rightarrow P=2\left(102\right)=204m$

Therefore, The perimeter of the rectangle is $204m$.