Find the resistance across (i) A and D (ii) B and D.

Open in App

Solution

Given: a circuit
To find the resistance across (i) A and D (ii) B and D.
Solution:
(i) The given circuit can redrawn as shown in fig(i)
The effective resistance of $2 Ω, 2 Ω$ in series.
$R_{s} = R_{1} + R_{2} = 2 + 2 = 4 Ω$
Circuit reduces to as shown in fig(ii)
Effective resistance of $4 Ω, 4 Ω, 4 Ω$ in parallel is
$\frac{1}{R_{A D}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} ⟹ \frac{1}{R_{A D}} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4} ⟹ R_{A D} = \frac{4}{3} = 1.33 Ω$
is the resistance across AD
(ii) The resistance across BD is also equal to the resistance across AD
Hence $R_{B D} = 1.33 Ω$

Suggest Corrections

Similar questions

\frac{d y}{d x} + y = \frac{1}{\frac{d y}{d x}}

_{e} [\frac{d y}{d x} - \frac{d^{3} y}{d x^{3}}] = l n [\frac{d^{5} y}{d x^{5}} + 1]

{[(\frac{d y}{d x})^{1 / 3} + y]}^{2} = \frac{d^{2} y}{d x^{2}}

i) \int \frac{x^{2} + 1}{x^{4} + 1}

i i) \int \frac{d x}{x^{2} + 1}

A

B

A

B

A

B

Join BYJU'S Learning Program