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Question

Find the roots of 1x1x2=3

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Solution

We have,

1x1x2=3

x2xx(x2)=3

2(x22x)=3

2=3x26x

3x26x+2=0 ……. (1)

We know that

x=b±b24ac2a

Therefore,

x=6±624×3×22×3

x=6±36246

x=6±126

x=6±236

x=1±33

x=1±13

Hence, the roots of this equation are 1+13,113.


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