Find the roots of the equation x2−2xcosθ + 1 = 0.
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Solution: Given equation x2−2xcosθ + 1 = 0.
Roots of quadratic equation using quadratic formulae
x = −b+––√b2−4ac2a
x = 2cosθ+––√4cos2θ−42
= cosθ+––√cos2θ−1
= cosθ+––isinθ
= eiθ and e−iθ.
If α satisfies the equation x2−2xcosθ+1=0. Find the value of αn + 1αn n ϵ Z