Question

Find the slope of the line whose inclination is:​
(ii) ${30}^{\circ }$

Answer 1

Given ,
Inclination , $\theta ={30}^{\circ }$
We know that , the slope of a line is given by the $\tan$ of its inclination .
$\therefore \text{slope}=\tan \theta$
$\Rightarrow \text{slope}=\tan {30}^{\circ }$
$\Rightarrow \text{slope}=\frac{1}{\sqrt{3}}$
Hence, the slope of the given line is $\frac{1}{\sqrt{3}}$