Question

Find the square root of :

(i) $\frac{1764}{2809}$ (ii) $\frac{507}{4107}$

(iii) $\sqrt{108\times 2028}$ (iv) $0.01+\sqrt{0.0064}$

Answer 1

(i) $\frac{1764}{2809}$

Hence, square root of $\sqrt{\frac{1764}{2809}}=\frac{42}{53}$

(ii) $\frac{507}{4107}=\frac{507÷3}{4107÷3}=\frac{169}{1369}$

Hence, square root of $\sqrt{\frac{169}{1369}}=\frac{13}{37}$

(iii) $\sqrt{108\times 2028}=\sqrt{219024}$

Hence, $\sqrt{108\times 2028}=468OR\sqrt{108\times 2028}$

= $\sqrt{2\times 2\times 3\times 3\times 3\times 2\times 2\times 3\times 13\times 13}$

= $\sqrt{2\times 2\times 2\times 2\times 3\times 3\times 3\times 3\times 13\times 13}$

= $2\times 2\times 3\times 13=468$

(iv) $0.01+\sqrt{0.0064}$

=0.01 +0.08 = 0.09