The correct option is A 0
The general term of the series is Tr=(−1)r(3+5r)nCr
where r = 0, 1, 2, ..., n. Therefore, sum of the series is given by
S=n∑r=0(−1)r(3+5r)nCr
=3(n∑r=0(−1)r nCr) + 5(n∑r=1(−1)rnn−1Cr−1)
=3(n∑r=0(−1)r nCr) - 5n(n∑r=1(−1)r−1 n−1Cr−1)
=3(1−1)n−5n(1−1)n−1
=0