Find the sum : (– 9) + 4 + 12 + (– 3) + 8

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-12

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Solution

The correct option is A 12
(– 9) + 4 + 12 + (– 3) + 8
Rearrange the positive and negative integers grouped together,
= (– 9) + (– 3) + 12 + 4 + 8
= -9 - 3 + 12 + 4 + 8
= -12 + 12 + 4 + 8
= 0 + 4 + 8
= 12
Thus, the sum of (– 9) + 4 + 12 + (– 3) + 8 is 12.

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Similar questions

Find the sum:
$\frac{9}{14} + \frac{8}{12}$

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

\frac{3}{4 \cdot 8} - \frac{3 \cdot 5}{4 \cdot 8 \cdot 12} + \frac{3 \cdot 5 \cdot 7}{4 \cdot 8 \cdot 12 \cdot 16} - . . . . . .

\frac{2}{3} - \frac{4}{9} + \frac{8}{27} - \frac{16}{21} + . . . . . . . .

(\frac{3}{4} \div \frac{9}{8}) \times 12

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