Question

Find the sum:

$\frac{1}{9}+\frac{4}{9}+\frac{7}{9}$

Answer 1

Find the Lowest Common Multiple (LCM) of the denominators and then simplify the fraction .

$\frac{1}{9}+\frac{4}{9}+\frac{7}{9}$

Here, the LCM of the denominator $9,9$and $9=9$ Therefor ,

$$\begin{gathered} \frac{1}{9}+\frac{4}{9}+\frac{7}{9} \\ \frac{1+4+7}{9}=\frac{\cancel{12}}{\cancel{9}}=\frac{4}{3} \end{gathered}$$

Since, $\frac{4}{3}$ in improper fraction $\frac{4}{3}=1\frac{1}{3}$

Hence,$\frac{1}{9}+\frac{4}{9}+\frac{7}{9}=\frac{4}{3}$ = $1\frac{1}{3}$