1
Question
Find the sum of 1+\dfrac{1}{2}+0+... to 20 terms.
Open in App
Solution
S=1+12+0+... to 20 termsa=1,d=12−1=−12,n=20S20=202[1+(20−1)−12]=10[1−192]=10×2−1925×−17=−75
S=1+12+0+... to 20 terms
a=1,d=12−1=−12,n=20
S20=202[1+(20−1)−12]
=10[1−192]
=10×2−192
5×−17=−75
Suggest Corrections
0
