Question

Find the sum of exterior angles $x+y+z+p+q$.

Answer 1

The measure of each exterior angle of an equiangular n-gon is,

$=\frac{360}{n}$

for a pentagon $n=5$

$=\frac{360}{5}$

$=72$

$\Rightarrow x=y=z=p=q=72$

$\therefore x+y+z+p+q=72+72+72+72+72=360$