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Question

Find the sum of n terms of AP18,1512,13,..

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Solution

Given,

a=18

d=31218=52

Formula,

an=a+(n1)d

=18+(n1)(52)

an=415n2

Sn=n2[2a+(n1)d]

=n2[2(18)+(n1)(52)]

=n2[415n2]

Sn=41n5n24

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