Find the sum of the order and degree of the differential equation $y = x {(\frac{d y}{d x})}^{3} + \frac{d^{2} y}{d x^{2}}$

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Solution

The order is 2 as the highest derivative is 2.
The degree is 1 as the highest derivative is of order 1.
Hence, the sum of the order and degree of the differential equation $y = x {(\frac{d y}{d x})}^{3} + \frac{d^{2} y}{d x^{2}}$ is 2 + 1 = 3

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Similar questions

Find the sum of the order and degree of the given differential equation : y = x ${(\frac{d y}{d x})}^{3} + \frac{d^{2} y}{d x^{2}} .$

\frac{d^{2} y}{d x^{2}} + \sqrt[3]{\frac{d y}{d x}} + (x + 1) = 0

y^{''} + 3 y^{'^{2}} + y^{3} = 0

{(\frac{d y}{d x})}^{2} + \frac{1}{d y d x} = 2

\frac{d^{2} y}{d x^{2}} + 4 y = 0

\frac{d^{2} y}{d x^{2}} + x {(\frac{d y}{d x})}^{2} = 2 x^{2} \log (\frac{d^{2} y}{d x^{2}})

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