Find the sum of zeros of : $(x + 1) (x^{4} - x^{3} + x^{2} - x + 1) = 0$

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Solution

According to the theory of equation, Sum of zeros of $x^{4} - x^{3} + x^{2} - x + 1 = 0$ is

$= - \frac{c o e f f i c i e n t o f x^{3}}{c o e f f i c i e n t o f x^{4}}$

$= - \frac{- 1}{1}$

$= 1$

Zeros of $x + 1 = 0$ is $- 1$

So the sum of zeros of the given equation is $= 1 - 1 = 0$

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