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B
95.5N
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C
100.2N
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D
102N
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Solution
The correct option is A82.5N Let the acceleration a of the 5 kg block be towards right
So, from the FBDs of both the masses, we have 15g−T=15a.....................(i) T−60=5a..........................(ii)
On solving both the equation (i) & (ii) we have, a=4.5m/s2
Thus, from the FBD of 15Kg body, tension T in the string is given as 15g−T=15a⟹T=15(g−a)=15×5.5 ⟹T=82.5N
Alternate:
Supporting force 15g=15×10=150N>60N
Hence, 15kg body will move downwards. So, the acceleration of the system is given by a=Supporting Force - Opposing forceTotal mass =150−6020=9020=4.5m/s2
So, from FBD of 5kg body tension T in the string is given as T−60=5a ⇒T=60+5(92)=82.5N