Find the third proportional to Rs. $2.40$ , Rs. $4.80$ .

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Solution

$\begin{matrix} R s 2.40, R s 4.80 t h e n, \frac{4.8}{2.4} = \frac{2}{1} p r o p o r t i o n t h i r d p r o p o r t i o n i s 2.4 \times 4 = 9.6 R u p e e s 9.6 \end{matrix}$

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Find the third proportional to Rs. 2.40, Rs. 4.80.

Rs2.40,Rs4.80then,4.82.4=21proportionthirdproportionis2.4×4=9.6Rupees9.6

Find the third proportional to Rs. $2.40$ , Rs. $4.80$ .

$\begin{matrix} R s 2.40, R s 4.80 t h e n, \frac{4.8}{2.4} = \frac{2}{1} p r o p o r t i o n t h i r d p r o p o r t i o n i s 2.4 \times 4 = 9.6 R u p e e s 9.6 \end{matrix}$