Find the value of 25- 52-

The correct option is C 800 Given 2^5 × 5^2. = 2 × 2 × 2× 2× 2 × 5× 5 ⇒ 32 × 25 = 800 ...

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Question

Find the value of $2^{5} \times 5^{2}$ .

600

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700

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800

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900

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\frac{25}{k} = 1^{2} - \frac{2^{2}}{5} + \frac{3^{2}}{5^{2}} - \frac{4^{2}}{5^{3}} + \frac{5^{2}}{5^{4}} - \frac{6^{2}}{5^{2}} + . . . . . . \infty

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(3^{0} - 4^{0}) \times 5^{2}

a

9 x^{2} + (7 a - 5) x + 25 = (3 x + 5)^{2}

Find the value of $5^{2} \times 4^{2}$

\frac{25}{k} = 1^{2} - \frac{2^{2}}{5^{2}} + \frac{2^{3}}{5^{3}} - \frac{4^{2}}{5^{4}} + \frac{2^{5}}{5^{5}} - \frac{2^{6}}{5^{6}} + . . . . . \infty

k

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