Find the value of
$(2 k m 120 m) + (3 k m 5 m) - (1 k m 525 m)$ .Giving your answer in $k m$

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Solution

Step 1- Conversion of $k m into m$
We know,
$1 k m = 1000 m$
$\Rightarrow 2 k m = 2 \times 1000 = 2000 m \Rightarrow 3 k m = 3 \times 1000 = 3000 m \Rightarrow 1 k m = 1 \times 1000 = 1000 m$
Now given expression becomes
$\begin{array}{rcl} (2 k m 120 m) + (3 k m 5 m) - (1 k m 525 m) & = & (2000 + 120) m + (3000 + 5) m - (1000 + 525) m \\ = & 2120 m + 3005 m - 1525 m \end{array}$
Step 2- Simplify :
We have, $2120 m + 3005 m - 1525 m$
Adding the numbers with same sign we get,
$2 1 2 0 m + 3 0 0 5 m 5 1 2 5 m$
Now,
$5 1 2 5 m - 1 5 2 5 m 3 6 0 0 m$
Therefore, $(2 k m 120 m) + (3 k m 5 m) - (1 k m 525 m) = 3600 m$
Step 3- Conversion of $m i n t o k m$
We know that, $1 m = \frac{1}{1000} k m$
$\Rightarrow 3600 m = \frac{1}{1000} \times 3600 = 3.6 k m$
Therefore, the value of $(2 k m 120 m) + (3 k m 5 m) - (1 k m 525 m)$ is $3.600 k m$ .

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