Find the value of ( $3^{0}$ + $4^{- 1}$ ) × $2^{3}$ . ___

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Solution

Given, ( $3^{0}$ + $4^{- 1}$ ) × $2^{3}$

Now, $4^{- 1}$ = $\frac{1}{4}$ ( $∵ a^{- 1} =$ $\frac{1}{a}$ ),

and, $3^{0}$ = 1( $∵ a^{0} = 1, w h e r e a \neq 0$ )
So, ( $3^{0}$ + $4^{- 1}$ ) × $2^{2}$ = (1+ $\frac{1}{4})$ × $2^{3}$
= $\frac{4 + 1}{4} \times 2^{3}$

= $5 \times 2$

= $10$

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