Find the value of $35^{2} + 47^{2}$ .

1454

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2834

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3434

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3439

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Solution

The correct option is C $3434$
35 ends with 5 so the last two digits will be 25 (_ _ 25)
The first two digits can be found as $3 \times 4 = 12$
So, $35^{2} = 1225$

$47^{2} = (50 - 3)^{2}$
$47^{2} = (50 - 3) \times (50 - 3)$
$47^{2} = (50 \times 50) + (50 \times - 3) + (- 3 \times 50) + ((- 3) \times (- 3))$
$47^{2} = 2500 - 150 - 150 + 9$
$47^{2} = 2209$

$⟹ 35^{2} + 47^{2} = 1225 + 2209$
$35^{2} + 47^{2} = 3434$

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Similar questions

Find the value of $36^{2} - 35^{2} =$

\frac{43^{3} + 47^{3}}{43^{2} - 43 \times 47 + 47^{2}}

\frac{43^{3} + 47^{3}}{43^{2} - 43 \times 47 + 47^{2}}

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