Find the value of : $999^{2}$

949321

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994521

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992201

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998001

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Solution

The correct option is D $998001$
$(1000 - 1)^{2}$
Using $(a - b)^{2} = a^{2} + b^{2} - 2 a b$
$= (1000 - 1)^{2}$
$= (1000)^{2} + (1)^{2} - 2 (1000) (1)$
$= 1000000 + 1 - 2000$
$= 998001$

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Similar questions

Observe the given pattern.

992 = 9801

9992 = 998001

Using the pattern, we get 99992 =

Whats the value of $1001^{2}$ - $999^{2}$ ?

{(999)}^{2}

(999)³

999 \frac{1}{7} + 999 \frac{2}{7} + 999 \frac{3}{7} + 999 \frac{4}{7} + 999 \frac{5}{7} + 999 \frac{6}{7}

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