Find the value of $(a + b + c + d)$ if $a = 3, b = - 5, c = - 11, d = - 3$ .

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Solution

To find

$(a + b + c + d)$

Given,

$a = 3, b = - 5, c = - 11, d = - 3$

$∴ a + b + c + d = 3 - 5 - 11 - 3 = - 16$

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If $B + C = 11, C + D = 19$ and $A + B = 5$ , find the value of $D + E$ .

यदि $B + C = 11, C + D = 19$ और $A + B = 5$ , तो $D + E$ का मान ज्ञात करें?

\frac{11 a^{2} + 9 a c}{11 b^{2} + 9 b d} = \frac{a^{2} + 3 a c}{b^{2} + 3 b d}

\sqrt{\frac{a^{2} + 5 c^{2}}{b^{2} + 5 d^{2}}} = \frac{a}{b}

\frac{a^{2} + a b + b^{2}}{a^{2} - a b + b^{2}} = \frac{c^{2} + c d + d^{2}}{c^{2} - c d + d^{2}}

\frac{1}{3}

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$i f \frac{5 + 2 \sqrt{3}}{7 + 4 \sqrt{3}} = a + b \sqrt{3}$

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