Question

Find the value of $c$, if $x-2$ is the factor of $x^3+x^2+cx+7$.

• A. 19
• B. $\frac{-19}{2}$
• C. $\frac{18}{2}$
• D. $\frac{-18}{2}$

Answer 1

Answer: (B)

$\frac{-19}{2}$

$x^3+x^2+cx+7$
$=(2{)}^3+(2{)}^2+c\times x+7$
$=8+4+7+2c$
$=12+7+2c$
$\to 19+2c=0$
$\to 2c=-19$
$\to c=\frac{-19}{2}$