Question 110
Find the value of (0.2×0.14)+(0.5×0.91)(0.1×0.2).
Given , (0.2×0.14)+(0.5×0.91)(0.1×0.2).∵0.2=210,0.14=14100 and 0.5=5100.91=91100,0.1=110 and 0.2=210∴(0.2×0.14)+(0.5×0.91)(0.1×0.2)=(210×14100)+(510×91100)(110×210)=281000+45510002100=28+45510002100=48310002100=4831000×100248310×2=241.510=24.15