Find the value of tan−1(√3)−cot−1(−√3)
tan−1√3−cot−1(−√3)=tan−1tanπ3−cot−1cot5π6=π3−5π6=−3π6=−π2
Find the value of tan−1(−1√3)+cot−1(1√3)+tan−1[sin(−π2)].